ANSWER: The guidelines your discover for instance the you to you price apply just when the fees will be looked at as a continuous water which can bequeath alone out on one epidermis, in spite of how higher, and have zero thickness. Of course, a situation like you establish, having 5 too-much electrons is within not a way such as for example a fluid and that i do guess that many techniques from 5-0 in order to 0-5 could be the distribution over a period. The theory is that, the five electrons do plan on their own so that for every single was due to the fact well away from the other cuatro that you could, however, indeed there would not be a separate instance shipment.
QUESTION: Can it be you can easily to suspend a keen electron through electrostatic levitation within the an excellent uniform magnetic career? While the latest voltage are diminished enough therefore, the electrostatic push with the electron is actually lower than the brand new push due to the latest electron’s lbs perform brand new electron upcoming experience good ‘fall’ owed so you’re able to gravity?
I’m asking this because I am curious when the establishing an excellent positron during the a good consistent magnetized profession (in a vacuum) and you will decreasing the voltage to a very quick worth so that new electrostatic push is gloomier as compared to weight manage end up in a beneficial positron so you’re able to including feel a ‘fall’. Whenever they performed sense a fall it may be determined if this manage slip right up otherwise down.
From the inertial bulk I mean the fresh proportion of the push you apply to it divided from the their acceleration, this means that their resistance to being accelerated
I am 17 years old and also in the united kingdom going to study physics in the school from inside the september and you will was only interested in learning it since the one of the subjects this current year are electric phenomena and you can i discussed millikan’s petroleum drop try which searched the same kind of suspension when the electrostatic push and you may force due to the law of gravity was indeed well-balanced.
Today, we know so you’re able to extraordinary reliability that inertial mass of a want Adult datings dating site reviews good positron is equal to the newest inertial mass regarding an enthusiastic electron
ANSWER: It is always nice to see young folks asking interesting questions. First, I need to correct one thing: everywhere you refer to a “magnetic field” you should say “electric field”; a magnetic field exerts no force on a charge at rest which is what you want to observe, la Millikan. (A more correct way, relativistically, to say this would be that they have equal momenta for equal speeds.) I believe it is true that nobody has ever “weighed” a positron by measuring the force it experiences in a gravitational field. But, if the gravitational mass were different from the inertial mass, this would fly in the face of the theory of general relativity. But, let’s talk about the feasibility of your experiment. The mass of an electron is about 10 -30 kg so its weight would be about 10 -29 N (taking g?10 m/s 2 ). The electron charge is about 1.6×10 -19 C and so the electric field required to levitate an electron would be 10 -29 /1.6×10 -19 ?6×10 -11 V/m. Suppose we use a parallel plate capacitor to create this field. The charge density ? on a plate with field E is about ?=?0E?10 -11 x6x10 -11 =6×10 -22 C/m 2 which would correspond to an electron density on the plates of about 6×10 -22 /1.6×10 -19 ?0.004 electrons/m 2 ! This would correspond to about one electron for every 250 square meters! That would not give a very uniform field would it? There is no such thing as a uniform surface charge density because charges in nature do not comprise a continuous fluid; so really tiny uniform fields are not possible. I did all that just for the fun of it, but there is an even more serious considerationthe earth itself has an electric field near the surface of typically 100 V/m pointing down, so an electron would be repelled upward. To do your experiment you would have to get rid of that field and I do not believe that it would be possible to be assured that you could make the residual field much less than your 6×10 -11 V/m. Back to the drawing board! Keep asking those hard and interesting questions, though, and good luck with your university studies.